Topic: Problem with storing in database

what is wrong ? i have no mistake on browser, but it don't store data in my DataBase.
<!DOCTYPE html>
<html>
<head>
    <title></title>
</head>
<body>
<form method="post" action="LogIn.php" >
    Introduce Login:

    <input type="text" name="login" required>


    Introduce Email:

    <input type="email" name="email" required>


    Introduce parola:

    <input type="password" name="parola" required>


    Introduce numele:

    <input type="text" name="nume" required>


    Introduce prenumele:

    <input type="text" name="prenume" required>


    Data nasterii:

    <input type="date" name="data" required>


   
    <input type="submit" name="submit" value="Trimite">
</form>
</body>
</html>
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______________________________________
<!DOCTYPE html>
<html>
<head>
    <title></title>
    <form method="post" action="log.php" >
        <input type="submit" name="sub" value="Login">
    </form>
</head>
<body>
<?php
    echo "Bine team regasit in obstina noatrsa Dl ".$_POST['nume']." ".$_POST['prenume']."
";
    echo "Vam trimis un mesaj de confirmare pe email-ul Dvs ".$_POST['email'];
?>
<?php
    $dbname = "client";
    $servername = "localhost";
    $username = "root";
    $password = "";

    $link = mysqli_connect($servername, $username, $password, $dbname)
                            or die ('Nu s-a conectat' . mysql_error());
    $login = $_POST['login'];
    $email = $_POST['email'];
    $pass = $_POST['parola'];
    $nume = $_POST['nume'];
    $prenume = $_POST['prenume'];
    $data = $_POST['data'];
    $sql = "INSERT INTO client1 (login, email, parola, nume, prenume, data)
                      VALUES ($login, $email, $pass, $nume, $prenume, $data)";
    mysqli_close($link);
  ?>
</body>
</html>

Re: Problem with storing in database

You forgot mysqli_query($sql)

Re: Problem with storing in database

I have some issues while creating the Backend for best essay writing service reviews's website. I am fed up with these continuous database error. I was looking for a place to find the errors in my MySQL query.